How to Extract All the Numbers Contained in a String in Python

Using List Comprehension

List comprehensions provide a concise way to create lists.

If you only want to extract only positive integers, try the following:

#!/usr/bin/python3

s = "The 2.0L 2023 AMG C 63 Wagon"

l = [int(c) for c in s.split() if c.isdigit()]
print(l)

[2023, 63]

The other solution is:

#!/usr/bin/python3

s = "The2.0L2023AMGC63Wagon"

s = ''.join((ch if ch in '0123456789.' else ' ') for ch in s)
l = [float(i) for i in s.split()]
print(l)

[2.0, 2023.0, 63.0]

Using Regexp

A more robust version would be:

#!/usr/bin/python3

# Import module
import re

s = "The2.0L2023AM.GC63Wagon"

l = re.findall(r'[-+]?(?:\d*\.\d+|\d+)', s)
print(l)

[2023, 63]

To catch different patterns it is helpful to query with different patterns.

different number patterns
'[\d]+[.,\d]+'
(finds commas) 12,300 or 12,300.00
'[\d]*[.][\d]+'
(finds floats) 0.123 or .123
'[\d]+'
(finds integers) 123
'[\d]+[.,\d]+|[\d]*[.][\d]+|[\d]+'
(finds integers) 123
'[\d]+'
Combine with pipe ( | ) into one pattern with multiple or conditionals.